【5 steps】Electronic Configuration of iodine or for iodine (I) in Just 5 Steps
Electronic Configuration of iodine or for iodine
To do or find or writing electronic configuration of iodine(I),we will follow just 5 steps.
Step-1:
To do electronic configuration of iodine(I),we have to know the atomic number of iodine(I).
The atomic number of iodine(I) is 53.So it has 53 electrons and 53 protons.
The atomic number of iodine(I) is 53.So it has 53 electrons and 53 protons.
Look how I find the electronic configuration of iodine(I)).
.
.
This process is applicable for all the elements of the periodic table.
Step-2:
(How do you remember the order of electron configurations?)
Now we have to memorize the following sequence of the orbitals.
ss
ps ps
dps dps
fdps fdps fdps fdps....
In a line-
ss ps ps dps dps fdps fdps
fdps fdps fdps fdps.......
Step-3:
Now we have to first number the s-orbital (start with 1s)like this:
1s2s
p3s p 4s
dp 5s dp 6s
fdp7s fdp 8s...... According to your need.
In a line-
1s2s p3s p 4s dp 5s dp 6s
fdp7s fdp 8s........
Remember
● s-orbital start with 1s
● p-orbital start with 2p
● d-orbital start with 3d
● f-orbital start with 4f
Again,Now(second) we need number the p-orbital(start with 2p) like this:
ss
2ps 3ps
d 4ps d 5ps
fd6ps fd7ps fd8ps fd9ps....
In a line--
ss 2ps 3ps d4ps d5ps
fd6ps fd7ps fd8ps fd9ps....
Thirdly,we need number the d-orbital(start with 3d)like this:
ss
ps ps
3dps 4dps
f5dps f6dps f7dps f8dps....
In a line--
ss ps ps 3dps 4dps
f5dps f6dps f7dps f8dps....
Fourthly,number the f-orbital(start with 4f) like this:
ps ps
dps dps
4fdps 5fdps 6fdps 7fdps....
In a line--
ss ps ps dps dps 4fdps 5fdps 6fdps 7fdps......
Fifltly,number s,p,d,f together like this....
1s2s
2p3s 3p4s
3d4p5s 4d5p6s
4f5d6p7s 5f6d7p8s
6f7d8p9s.........
In a line----
1s 2s 2p 3s 3p 4s 3d 4p 5s d 5p 6s 4f 5d 6p 7s 5f 6d 7p 8s
6f 7d 8p 9s.........
How do you remember the order of electron configurations?
|
Step-4:
(What is spdf in electron configuration?
think--)
Now we have to know that
Now we have to know that
•S-orbital can take maximum 2 electrons.
•p-orbital can take maximum 6 electrons.
•d-orbital can take maximum 10 electrons.
•f-orbital can take maximum 14 electrons.
How to Do or Find Electron Configuration |
Step-5:
Now we know that iodine(I) has 53 electrons.
Electron configuration of
iodine(I) will be...
s² s²
p⁶s² p⁶s²
d¹ºp⁶s² d¹ºp⁵s
fdps fdps fdps....
So,we are getting..
s² s²
p⁶s² p⁶s²
d¹ºp⁶s² d¹ºp⁵
Now number s-orbitals according to above process.
1s² 2s²
p⁶3s² p⁶4s²
d¹ºp⁶5s² d¹ºp⁵
Now number the p orbitals according to above process.
1s² 2s²
2p⁶3s² 3p⁶4s²
d¹º4p⁶5s² d¹º5p⁵
Now number d orbitals according to above process......
1s² 2s²
2p⁶3s² 3p⁶4s²
3d¹º4p⁶5s² 4d¹º5p⁵
Now arrange this--low to high value of n
1s²2s²2p⁶3s²3p⁶ 3d¹º4s²4p⁶4d¹º5s²5p⁵
So the electronic configuration of iodine(I) is
1s²2s²2p⁶3s²3p⁶ 3d¹º4s²4p⁶4d¹º5s²5p⁵
●What is the electron configuration of iodine(I)?
Ans:
1s²2s²2p⁶3s²3p⁶3d¹º4s²4p⁶
4d¹º5s²5p⁵
4d¹º5s²5p⁵
Valence Electron configuration,number of valency electrons and valency shell of iodine(I)
5s²5p⁵
Valence Electron configuration,number of valency electrons and valency shell of iodine(I)
5s²5p⁵
Comments
Post a Comment