Chemistry291

Oxidation of Ethene or Ethylene(CH2=CH2) Solution: Today we will talk about the oxidation of ethene. In ethene, the oxidation number of every carbon is -2. When we apply mild oxidising conditions to ethene,we get ethane-1,2-diol. In mild oxidising conditions, the oxidising agent is kept cold at room temperature. For mild oxidation of ethene,we use alkaline solution of KMnO4 (potassium permanganate). Oxidation of Ethene (CH2=CH2) In the above reaction, ethene has lost electrons,so ethene has oxidized.Look at the change of oxidation number from -2 to -1. When we apply strong oxidizing conditions to ethene using hot and concentrated potassium permanganate solution,we get carbon dioxide and water. The production of CO₂ and H₂O from strong oxidation of ethene is given below. In the above reaction, ethene has lost electrons,so ethene has oxidized.Look at the change of oxidation number from -2 to +4.

Answer: Ammonia, NH3 , has eight valence electrons. Explanation: Today we are going to determine the valence electrons for NH3(Ammonia). Step-1: Nitrogen is the element of group VA.This means that nitrogen has five valence electrons. On the other hand, hydrogen is the element of group IA.This means that hydrogen has one valence electrons. Step-2: For ,NH3 N → 5 3×H → 1×3=3 So, totally we have (8) eight valence electrons in NH3,five from nitrogen and three from three hydrogen atom. NH3 Lewis Structure NH3 Lewis structure Continue

How Many Valence Electrons Does CO2 (Carbon Dioxide) Have? Answer: CO2 has 16 valence electrons ,four from carbon and twelve from two oxygen atom. Explanation: Today we are going to determine the valence electrons for CO2 (Carbon Dioxide).                Step-1: Carbon is the element of group IV A.This means that carbon has four valence electrons. On the other hand, oxygen is the element of group VIA.This means that Oxygen has six valence electrons.                    Step-2: For ,CO2 C    →   4 2×O   →   6×2=12 So, totally we have 16 valence electrons in CO2,four from carbon and twelve from two oxygen atom. Continue CO2 Lewis Structure

Oxidation of Magnesium (Mg) Today,from this post we will learn about the oxidation of magnesium (Mg). Remember that the oxidation of magnesium (Mg) means the oxidation number of magnesium (mg) , the oxidation state of magnesium (Mg) or how many electrons magnesium (mg) usually loses. To know the oxidation of magnesium (Mg),at first we have to find out the valence electrons in magnesium (Mg) from its electronic configuration. Mg(12)=1s² 2s² 2p⁶ 3s² =【Ne】3s² Magnesium (Mg) is a metal.So it will lose electrons from its valence Valence shell.Valence shell is the outer mostshell and valence electrons are the electrons of valence shell. Mg(12)=1s² 2s² 2p⁶ 3s² =【Ne】3s² So,magnesium (mg) has 2 valence electrons. During reactions (as we know that only valence electrons can take part)  magnesium can lose maximum two electrons. Usually, magnesium (mg) shows +1, and+2,oxidation number or oxidation states. For showing +2 oxidation state,magnesium (mg) lose two electrons from 3s orbital.

Oxidation of Nickel (Ni) Today,from this post we will learn about the oxidation of nickel. Remember that the oxidation of nickel means the oxidation number of nickel , the oxidation state of nickel or how many electrons nickel usually loses. To know the oxidation of nickel,at first we have to find out the valence electrons in nickel from its electronic configuration. Ni(28)=1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁸ =1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁸ 4s² =【Ar】3d⁸ 4s² Nickel is a transitional metal.So,we have to consider d orbital as part of its valence shell.Valence shell is the outer mostshell and valence electrons are the electrons of valence shell. Ni(28)=【Ar】3d⁸ 4s² So,nickel has 10 valence electrons.But this does means that nickel will use all the valence electrons during reactions as we know that only valence electrons take part during a reaction. Usually, nickel shows 0,+1,+2,+3 and +4 oxidation number or oxidation states. For showing +2 oxidation state,nickel lose two electrons

SF4 Lewis Structure SF4 Lewis structure(Sulfur tetrafluoride electron dot structure) is that type of diagram where we show the total 34 valence electrons of SF4 as dots , or dots and dashes(-).In Lewis structure,it is common that a bonding pair of two electrons can be shown by  dash(-) or dots(●●) but a lone pair of two electrons is shown by dots[●●]. Explanation: Hello,today I am going to draw the SF4 Lewis structure  in just five steps.             SF4 Lewis Structure  Setup Step-1: To draw the SF4 Lewis structure , we have to find out the valence electrons of sulfur and fluorine first.We express valence electrons as dots in lewis dot structure. To get the valence electrons of sulfur,we need to look at the electronic configuration of sulfur. S(16)=1s²2s²2p⁶ 3s² 3p⁴ 3d The highest value of principal quantum number here is n=3. The highest value of principal quantum number ,n , indicates the valence shell and we know the electrons in valence shell is calle

 CS2 Lewis  Structure  Answer: CS2 Lewis structure(carbon disulfide electron dot structure) is that type of diagram where we show the total 16 valence electrons of CS2 as dots , or dots and dashes(-).In Lewis structure,it is common that a bonding pair of two electrons can be shown by  dash(-) or dots(●●) but a lone pair of two electrons is shown by dots[●●]. CS2 Lewis  Structure In CS2 Lewis structure,two double bonds are going from carbon to sulfur.There are four lone pairs in CS2 Lewis structure. In CS2 Lewis structure,the carbon atom follows the octet rule and the sulfur atoms  also follow the octet rule.Thus,in CS2,all follows the octet rule. In CS2 Lewis structure,we get eight pairs of electrons.Out of eight pairs of electrons,CS2 has four bond pairs and four lone pairs of electrons. Explanation: Hello,today I am going to draw the CS2 Lewis  structure   in just five steps.         CS2 Lewis  structure Setup  Step-1: To draw the CS2 lewis  structure  , we have to find ou

CCl4 Lewis Structure  Hello,today I am going to draw the CCl4 Lewis  structure for CCl₄ in just four steps.              CCl4 Lewis  Structure Setup Step-1 : To draw the CCl4 Lewis  structure (carbon tetrachloride), we have to find out the CC4 valence electrons   first.We express valence electrons as dots in lewis dot structure. To get the valence electrons of carbon,we need to look at the electronic configuration of carbon. C(6)=1s²2s²2p² The highest value of principal quantum number here is n=2. The highest value of principal quantum number ,n , indicates the valence shell and we know the electrons in valence shell is called valence shell. The nunber of valence electrons in carbon is 4. Now,to draw the lewis dot structure of carbon,we need to imagine a square around carbon.                   口 We know a square has four sides.At first,we have to place one valence electrons as dot to every side of that square before pairing up. Again, we have to find out the valence electrons o