Does H2S(Hydrogen sulphide) follow/obey the octet rule?
Yes,in the best Lewis structure of H2S(Hydrogen sulphide),the sulfur atom,S, follows/obeys the octet rule and the hydrogen atoms follow the duet rule .
Explanation:
The sulfur atom has 6 electrons in outermost shell or valence shell as it is the element of VIA. It shares 2 of its electrons each with 2 hydrogen atoms and thus it has two lone
pairs of electrons.
Thus 6 its and 2 that of two hydrogens completes its octet. While the hydrogens(H) completes their duplets.
In explanation,I will say that sulfur is a nonmetal and hydrogen is also a nonmetal.So,both atoms in H2S will share electrons in such a way that all atoms can achieve eight valence electrons or duet valence elctrons in their valence shells and thus can gain more stability.
In H2S ,the sulfur has shared two electrons with each Hydrogen and each hydrogen has shared two electrons with the sulfur atom.
By sharing ,the S atom in H2S, has achieved the eight valence electrons in its most occupied energy levels, and each hydrogen has achieved two valence electrons, So H2S follows/obeys the octet rule or duet rule.
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