How many valence electrons does iodine have?

Answer:
Iodine has seven valence electrons.

Explanation:

To find out the number of valence electrons in an iodine atom,we need to look at the periodic table.

The position of iodine in the periodic table is in group VIIA.For main group elements,valence electrons are equal to the group number.So,iodine atom has seven valence electrons in its valence shell or outermost energy level.

Again, iodine is an element of group 17.Now just consider the unit place digit from group number.You are getting 7 which is equal to the number of valence electrons in iodine.

Here is the another way to find out the valence electrons of iodine.

The symbol of iodine is I and the atomic number of iodine is 53.So,it has fifty three  electrons totally.

Now write the electronic configuration of iodine.

I(53) =1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d10 5s2 5p5

=[Kr]4d10 5s2 5p5

             

[Tip: Complete filled d orbital is not considered as part of  valence shell or energy level]

The valence shell is the outermost shell and the electrons that are present in valence shell is called valence electrons.

The valence shell or energy level can be identified by the highest value of principal quantum number,n.Here the highest value of n is 5.So,the valence shell is the 5th shell or energy level.

In 5th shell,we get seven valence electrons.So each iodine has seven valence electrons.

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