【】H2S Lewis Structure ,Valence Electrons ,Formal Charge,Polar or Nonpolar,Octet Rule
H2S Lewis Structure
Answer:
The definition of H2S Lewis structure or electron dot structure is given below:
H2S Lewis structure(Hydrogen disulphide electron dot structure) is that type of diagram where we show the total eight valence electrons of H2S as dots , or dots and dashes(-).In Lewis structure,it is common that a bonding pair of two electrons can be shown by dash(-) or dots(●●) but a lone pair of two electrons is shown by dots[●●].
In H2S Lewis structure, the atom sulfur follows the octet rule and the hydrogen atoms follow the duet rule.So,H2S molecule follows the octet rule.
In H2S Lewis structure,we get four pairs of electrons.Out of four pairs of electrons,H2S has two bond pairs and two lone pairs of electrons.
Explanation:
Hello,today I am going to draw the H2S Lewis structure in just four steps.
H2S Lewis structure Setup Step-1:
H2S Lewis structure Setup Step-1:
To draw the H2S Lewis structure , we have to find out the H2S total valence electrons first.We express valence electrons as dots in lewis dot structure.
To get the valence electrons of sulfur,we need to look at the electronic configuration of sulfur.
S(16)=1s²2s²2p⁶3s²3p⁴
The highest value of principal quantum number here is n=3.
The highest value of principal quantum number ,n , indicates the valence shell and we know the electrons in valence shell is called valence shell.
The nunber of valence electrons in sulfur is 6.
Again, we have to find out the valence electrons of hydrogen,H.
To get the valence electrons of hydrogen,we need to look at the electronic configuration of hydrogen.
H(1)=1s¹
The highest value of principal quantum number here is n=1.
The highest value of principal quantum number ,n , indicates the valence shell and we know the electrons in valence shell is called valence shell.
The nunber of valence electrons in hydrogen is 1.
Step-2:H2S Valence Electrons
Now we have to count total number of H2S valence electrons.
S =6
2×H=1×2=2
So, the total valence electrons for H₂S molecule valence are eight (6+2=8 ).
H2S Lewis structure Setup Step-3:
Now we have to determine the central atom in H₂S.The central atom is that kind of atom that is single or that has lower electronegativity.In case of H₂S,S is the central atom and H is the outer atom.Remember that hydrogen is always the outer atom.
H2S Lewis structure Setup Step-4:
Now we need to connect the outer atoms with the central atoms using dots or line(-).Every line represent two 【●●】dots or two valence electrons.
Or,
In the above structure,we have used 4 valence electrons iut of eigh.So,we have 8-4=4 valence electrons left .
Now we will use these 4 valence electrons to satisfy the octet for central atom.
Or,
The above structure is the H2S Lewis structure.
H2S Lewis Structure:Formal Charge
Now we can calculate the formal charge for each of atoms in H2S Lewis structure by applying the formula for formal charge.
H--->1-0-1 =0
Continue
Rule-4:
Formal Charge =Valence Electrons - unshared Electrons - 1/2 (Shared Electrons)
●The formal charge of sulphur is zero.
•Valence electrons of S =6
•Shared electrons of S= 4
•Unshared electrons of S =4
●F.C. of S =6- 4 -1/2(4)
=6-4-2
=6-6
=0
So,the best H2S Lewis dot structure will be the one where most atoms will have zero formal charge.Here is the best Lewis dot structure for H2S (Hydrogen sulphide).
Continue
●How many valence electrons does H2S have?
Answer:
H2S has eight valence electrons.Two valence electrons from two hydrogen atoms and six valence electrons from one sulfur atom.Thus,H2S valence electrons are eight.
●Is H2S polar or nonpolar?
Answer:
H2S is a polar molecule.Again,hydrogen sulphide is polar molecule because of its bent shape(V type shape) which makes the net molecular dipole moment non zero.Again,Since H2S has net molecular dipole moment,H2S is polar.
Explanation:
Here are the few steps that you help you to determine that hydrogen sulphide,H2S, is a polar molecule.
Step-1:
Draw the Lewis structure of H2S.
Step-2:
After drawing Lewis structure of H2S,now you need to consider the electronegativity difference between atoms.
Here sulphur is more electronegative than hydrogen.So,every sulphur-hydrogen bond is polar.
Step-3:
Now consider bond dipole moment.
As both sulphur- hydrogen bonds are polar,every bond has a dipole moment.
Step-4:
Now consider the geometry or shape of H2S molecule by applying VSEPR theory.
According to VSEPR theory,we get bent shape or geometry of H2S.
Step-5:
Now consider the net molecular dipole moment.
As the shape of H2S is bent(V type),one bond dipole moment does not cancel another bond's dipole moment.Thus,we get non zero value for the net molecular dipole moment .As the value of net molecular dipole moment is not zero,we can say that H2S is polar.
●Does H2S follow the octet rule?
Answer:
Yes,in the best Lewis structure of H2S,the sulfur atom,S, in H2S follows/obeys the octet rule and the hydrogen atoms follow the duet rule .In explanation,I will say that sulfur is a nonmetal and hydrogen is also a nonmetal.So,both atoms in H2S will share electrons in such a way that all atoms can achieve eight valence electrons or duet valence elctrons in their valence shells and thus can gain more stability.
In H2S ,the sulfur has shared two electrons with each Hydrogen and each hydrogen has shared two electrons with the sulfur atom.
By sharing ,the S atom in H2S, has achieved the eight valence electrons in its most occupied energy levels, and each hydrogen has achieved two valence electrons, So H2S follows/obeys the octet rule or duet rule.
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