【】How Many Valence Electrons Does Fluorine(F) Have?|fluorine valence electrons
Answer:
Fluorine (F) has seven valence electrons.
Explanation:
Step-3:
F(9)=1s²2s²2p⁵
Step-4:
F(9)=1s²2s²2p⁵
Now we will find out valence shell of fluorine from the electronic configuration of fluorine.
F(9)=1s²2s²2p⁵
F(9)=1s²2s²2p⁵
Step-5
F(9)=1s²2s²2p⁵
configuration
of fluorine,we see
that fluorine has 7
valence electron in its
valence shell.
Now I am going to show you how many valence electrons fluorine have in just 5 steps.
Step-1:
First, find the atomic number of fluorine from periodic table.
From periodic table ,we see that the atomic number of fluorine is 9.
Step-2:
We know that the atomic number of fluorine is 9.So fluorine has 9 protons and 9 electrons as the charge of electrons and protons are equal but opposite in nature.The charge of proton is +1 and the charge of electron is -1.
Step-3:
Now write the electron configuration of fluorine.
F(9)=1s²2s²2p⁵
Step-4:
F(9)=1s²2s²2p⁵
Now we will find out valence shell of fluorine from the electronic configuration of fluorine.
F(9)=1s²2s²2p⁵
Valence shell can be found from the highest number of principal quantum number.You know that principal quantum number is expressed by n.
F(9)=1s²2s²2p⁵
Here the highest value of n is 2.SoThe valence shell of fluorine is 2s²2p⁵
Step-5
In this step,we will find out the valence electrons of fluorine.
We have to know that the electrons of valence shell are called valence electrons.
F(9)=1s²2s²2p⁵
From the above electron
configuration
of fluorine,we see
that fluorine has 7
valence electron in its
valence shell.
So there are seven valence electrons of fluorine.
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