Is anion a positive ion?
Is anion a positive ion? Answer: No,an anion is not a positive ion.It is a negatively charged ion.
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Is a cation positive or negative?
Is a cation positive or negative? Answer: A cation is a positively charged ion. For example, Na+
【】How many unshared pairs of electrons are in this electronic configuration? 1s² 2s² 2p⁶ 3s² 3p³
This is not a right question the right question should be like this: How many unpaired electrons are in this electronic configuration? 1s² 2s² 2p⁶ 3s² 3p³ ? You will get three single electrons(unpaired) in 3px¹,3py¹ and 3pz¹ if consider Hund's rule. Explanation: Given electron configuration, 1s² 2s² 2p⁶ 3s² 3p³ You can rewrite this: 1s² 2s² 2p⁶ 3s² 3px¹,3py¹ 3pz¹ We know that 3p subshell has three degenerate orbitals which are 3px,3py and 3pz. These three orbitals have same energy.That is why each will take one electron first,then pairing of electrons happen.So we are getting three unpaired electrons. Next
[ ] What is the third quantum number of a 3s2 electron in phosphorus, 1s2 2s2 2p6 3s2 3p3 ?
What is the third quantum number of a 3s2 electron in phosphorus, 1s2 2s2 2p6 3s2 3p3 ? Answer: The third quantum number of a 3s2 electron in phosphorus, 1s2 2s2 2p6 3s2 3p3 is ml =0 .
Why 3d Subshell has more energy than 4s?
Why 3d Subshell has more energy than 4s? Answer: The n+l value for 3d subshell is higher than 4s subshell.That is why 3d subshell has higher energy than 4s subshell. Explanation: The sum of" n+ l "value determines the energy of an orbital.Here, n is the principal quantum number and l is the azimuthal quantum number. For l=0,we get "s" orbital. For l=1,we get "p" orbital. For l=2, we get "d" orbital. Now determine the energy of 4s and 3d subshell by applying n+l formula. For 4s ,n=4 and l=0 So,n+l is 4+0 =4 For 3d ,n=3 and l=2 So,n+l is 3+2 = 5 Here,we see that the n+l value for 3d subshell is higher than 4s,so 3d subshell has higher energy than 4s subshell. Next
【】Why is 3d higher in energy than 4s?
Why is 3d higher in energy than 4s? Answer: The n+l value for 3d orbital is higher than 4s orbital.That is why 3d has higher energy than 4s orbital. Explanation: The sum of" n+ l "value determines the energy of an orbital.Here, n is the principal quantum number and l is the azimuthal quantum number. For l=0,we get "s" orbital. For l=1,we get "p" orbital. For l=2, we get "d" orbital. Now determine the energy of 4s and 3d orbitals by applying n+l formula. For 4s ,n=4 and l=0 So,n+l is 4+0 =4 For 3d ,n=3 and l=2 So,n+l is 3+2 = 5 Here,we see that the n+l value for 3d is higher than 4s,so 3d has higher energy than 4s orbital. Next
【 】Why does 19th electron of K (Potassium)go to 4s orbital instead of 3d orbital?
Why does 19th electron of K go to 4s orbital instead of 3d orbital? Answer: The 19th electron or last electron of potassium (K) goes to 4s orbital instead of 3d orbital because the energy of 4s orbital is lower than 3d orbital. Explanation: According to Aufbau principal,an electron always goes to lower energy level or orbital first,then goes to higher energy levels or orbitals. The sum of" n+ l "value determines the energy of an orbital.Here, n is the principal quantum number and l is the azimuthal quantum number. For l=0,we get "s" orbital. For l=1,we get "p" orbital. For l=2, we get "d" orbital. Now determine the energy of 4s and 3d orbitals by applying n+l formula. For 4s ,n=4 and l=0 So,n+l is 4+0 =4 For 3d ,n=3 and l=2 So,n+l is 3+2 = 5 Here,we see that the n+l value for 4s is lower than 3d,so 4s has lower energy than 3d orbital.That is why t he 19th electron or last electron of potassium (K) goes t