The sum of 4 consecutive odd numbers is 40 . What is the second number in this sequence ?

Solution:

We need to find out the  second odd number  from  consecutive odd number sequence.

 

                      Step-1:

We have to have knowledge about odd number . If you divide a odd number by 2 ,you will get a remainder.,i.e. an odd number is not exactly divisible by 2.

Now you have to understand about consecutive odd number.The difference between two consecutive odd number  is always 2.

 

                Step-2:

Say,the first odd number is x.

So, the second odd number will be x+ 2. Thus, the third consecutive odd number will be x+4 .Besides,the fourth odd number will be x+6.

Have a look here.

The four consecutive odd numbers are x, x+2,x+4 ,x+6 respectively.

                  Step-3:

According to the conditions,the sum of 4 consecutive odd numbers will be 40.

 

So, we are getting the following equation

 

x +( x+2)+(x+4) +(x+6)  = 40

Or, 4x + 12 = 40

Or, 4x + 12 – 12 = 40 - 12[ Deduct 12 from both sides ]

Or, 4x + 0 = 28

Or, 4x = 28

Or, 4x/4 =  28/4

[Divide both sides by 4]

Or, x = 7

Now put the value of x here:

x, x+2,x+4 ,x+6

= 7, 7+2 , 7+4 ,7+6

=7,   9,    11,    13

So, the second number of this sequence is 13.

Answer: 13

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