Electronic Configuration of Fe is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶. The Order of Electron Removal in the Formation of Fe³⁺ is

Solution:

Given,

Fe(26)=1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶

Fe³⁺ =1s² 2s² 2p⁶ 3s² 3p⁶ 4s 3d⁵

The order of electron removal in the formation of Fe³⁺ is that we need to first remove two electrons from 4S as the principal quantum number ,n, has the highest value which is 4.After that,we need to remove one electron from 3d .This is because n+l value is higher for 3d than others.